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package syncx
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import "sync"
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type (
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// SharedCalls lets the concurrent calls with the same key to share the call result.
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// For example, A called F, before it's done, B called F. Then B would not execute F,
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// and shared the result returned by F which called by A.
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// The calls with the same key are dependent, concurrent calls share the returned values.
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// A ------->calls F with key<------------------->returns val
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// B --------------------->calls F with key------>returns val
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SharedCalls interface {
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Do(key string, fn func() (interface{}, error)) (interface{}, error)
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DoEx(key string, fn func() (interface{}, error)) (interface{}, bool, error)
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}
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call struct {
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wg sync.WaitGroup
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val interface{}
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err error
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}
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sharedGroup struct {
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calls map[string]*call
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lock sync.Mutex
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}
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)
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func NewSharedCalls() SharedCalls {
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return &sharedGroup{
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calls: make(map[string]*call),
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}
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}
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func (g *sharedGroup) Do(key string, fn func() (interface{}, error)) (interface{}, error) {
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c, done := g.createCall(key)
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if done {
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return c.val, c.err
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}
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g.makeCall(c, key, fn)
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return c.val, c.err
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}
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func (g *sharedGroup) DoEx(key string, fn func() (interface{}, error)) (val interface{}, fresh bool, err error) {
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c, done := g.createCall(key)
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if done {
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return c.val, false, c.err
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}
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g.makeCall(c, key, fn)
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return c.val, true, c.err
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}
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func (g *sharedGroup) createCall(key string) (c *call, done bool) {
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g.lock.Lock()
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if c, ok := g.calls[key]; ok {
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g.lock.Unlock()
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c.wg.Wait()
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return c, true
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}
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c = new(call)
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c.wg.Add(1)
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g.calls[key] = c
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g.lock.Unlock()
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return c, false
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}
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func (g *sharedGroup) makeCall(c *call, key string, fn func() (interface{}, error)) {
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defer func() {
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g.lock.Lock()
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delete(g.calls, key)
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g.lock.Unlock()
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c.wg.Done()
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}()
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c.val, c.err = fn()
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}
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